0=-1.7-0.2x+.0001x^2

Solution for 0=-1.7-0.2x+.0001x^2 equation:

0=-1.7-0.2x+.0001x^2

We move all terms to the left:

0-(-1.7-0.2x+.0001x^2)=0

We add all the numbers together, and all the variables

-(-1.7-0.2x+.0001x^2)=0

We get rid of parentheses

-.0001x^2+0.2x+1.7=0

We add all the numbers together, and all the variables

-0.0001x^2+0.2x+1.7=0

a = -0.0001; b = 0.2; c = +1.7;
Δ = b2-4ac
Δ = 0.22-4·(-0.0001)·1.7
Δ = 0.04068
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.2)-\sqrt{0.04068}}{2*-0.0001}=\frac{-0.2-\sqrt{0.04068}}{-0.0002}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.2)+\sqrt{0.04068}}{2*-0.0001}=\frac{-0.2+\sqrt{0.04068}}{-0.0002}
$